105x^2+96x-56=0

Solution for 105x^2+96x-56=0 equation:

105x^2+96x-56=0

a = 105; b = 96; c = -56;
Δ = b2-4ac
Δ = 962-4·105·(-56)
Δ = 32736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32736}=\sqrt{16*2046}=\sqrt{16}*\sqrt{2046}=4\sqrt{2046}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-4\sqrt{2046}}{2*105}=\frac{-96-4\sqrt{2046}}{210}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+4\sqrt{2046}}{2*105}=\frac{-96+4\sqrt{2046}}{210}
$